3^4x-7=27^2x+3

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Solution for 3^4x-7=27^2x+3 equation: 



3^4x-7=27^2x+3

We move all terms to the left:

3^4x-7-(27^2x+3)=0

We get rid of parentheses

3^4x-27^2x-3-7=0

We add all the numbers together, and all the variables

3^4x-27^2x-10=0

We move all terms containing x to the left, all other terms to the right

3^4x-27^2x=10

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